document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145751>Question 145751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help I am trying to fully understand how to find the real solutions of the system. I have no problem solving a problem like : x^2+2y^2=12 and 3x^2-y^2=8 but when the problem looks like this: xy+6=0 and x-y=-5 I cant figure out where to start. Your help would do a lot for me thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106369 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> xy+6=0<BR>\n" );
document.write( "x-y=-5 then x=y-5\r<BR>\n" );
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document.write( "then using the 1st eq we have (y-5)y+6=0 then y^2-5y+6=0\r<BR>\n" );
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document.write( "solving this eq solutions are 3 and 2 so y=2 or y=3\r<BR>\n" );
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document.write( "if y=2 then x=-3<BR>\n" );
document.write( "if y=3 then x=-2\r<BR>\n" );
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document.write( "Solutions are (-3,2) and (-2,3)\r<BR>\n" );
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