document.write( "Question 145753: how do I solve: c^3+c^2-7c-3=0, given root -3? \n" ); document.write( "
Algebra.Com's Answer #106366 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! First of all, note that this method is fairly advanced. If you don't understand what I'm doing, E-mail me what method you were supposed to use to solve this...\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'm going to change c to x. \n" ); document.write( "By the given information we have,\r \n" ); document.write( "\n" ); document.write( "(x+3)(ax^2+bx+c)=0\r \n" ); document.write( "\n" ); document.write( "and if we expand this out, we have: \n" ); document.write( "3 c + 3 b x + c x + 3 a x^2 + b x^2 + a x^3=0\r \n" ); document.write( "\n" ); document.write( "From this and the original coefficients 1, 1, -7, -3, respectively, it follows that: \n" ); document.write( "3c=-3, implies c=-1 \n" ); document.write( "3b+c=-7, implied 3b=-6, implies b=-2 \n" ); document.write( "3a+b=1, implies 3a=3, implies a=1.\r \n" ); document.write( "\n" ); document.write( "We don't have to solve the cubic coefficients.\r \n" ); document.write( "\n" ); document.write( "So, the original polynomial factors as: \n" ); document.write( "(x+3)(x^2-2x-1)=0 \n" ); document.write( "Now, we can solve for the other roots by applying the quadratic formulae: \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which gives \n" ); document.write( "So, all zeroes are \n" ); document.write( "\n" ); document.write( " |