document.write( "Question 145753: how do I solve: c^3+c^2-7c-3=0, given root -3? \n" ); document.write( "
Algebra.Com's Answer #106366 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
First of all, note that this method is fairly advanced. If you don't understand what I'm doing, E-mail me what method you were supposed to use to solve this...\r
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\n" ); document.write( "\n" ); document.write( "I'm going to change c to x.
\n" ); document.write( "By the given information we have,\r
\n" ); document.write( "\n" ); document.write( "(x+3)(ax^2+bx+c)=0\r
\n" ); document.write( "\n" ); document.write( "and if we expand this out, we have:
\n" ); document.write( "3 c + 3 b x + c x + 3 a x^2 + b x^2 + a x^3=0\r
\n" ); document.write( "\n" ); document.write( "From this and the original coefficients 1, 1, -7, -3, respectively, it follows that:
\n" ); document.write( "3c=-3, implies c=-1
\n" ); document.write( "3b+c=-7, implied 3b=-6, implies b=-2
\n" ); document.write( "3a+b=1, implies 3a=3, implies a=1.\r
\n" ); document.write( "\n" ); document.write( "We don't have to solve the cubic coefficients.\r
\n" ); document.write( "\n" ); document.write( "So, the original polynomial factors as:
\n" ); document.write( "(x+3)(x^2-2x-1)=0
\n" ); document.write( "Now, we can solve for the other roots by applying the quadratic formulae:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-2x%2B-1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-2%29%5E2-4%2A1%2A-1=8\".
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\n" ); document.write( " Discriminant d=8 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--2%2B-sqrt%28+8+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-2%29%2Bsqrt%28+8+%29%29%2F2%5C1+=+2.41421356237309\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-2%29-sqrt%28+8+%29%29%2F2%5C1+=+-0.414213562373095\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-2x%2B-1\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-2x%2B-1+=+1%28x-2.41421356237309%29%2A%28x--0.414213562373095%29\"
\n" ); document.write( " Again, the answer is: 2.41421356237309, -0.414213562373095.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-2%2Ax%2B-1+%29\"

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\n" ); document.write( "\n" ); document.write( "Which gives \"x=1%2B-sqrt%282%29\"
\n" ); document.write( "So, all zeroes are \"x=1%2B-sqrt%282%29\" and -3. We can see this in the following graph of the cubic:\r
\n" ); document.write( "\n" ); document.write( "\"graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E3%2Bx%5E2-7x-3+%29\"
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