document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145561>Question 145561</A>: <I><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( "       Find the solutions of 3x2/3 + 8x1/3 - 3 = 0.(eg.3 with u = x 1/3)\r<BR>\n" );
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document.write( "       College Algebra ISBN-13: 978-0-618-77629-0\r<BR>\n" );
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document.write( "       Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106361 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the solutions of 3x2/3 + 8x1/3 - 3 = 0<BR>\n" );
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document.write( "You have a quadratic with variable x^(1/3).\r<BR>\n" );
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document.write( "Let x^1/3 = w<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "3w^2 + 8w - 3 = 0<BR>\n" );
document.write( "Use the AC Method or \"Reverse Foil\" to factor the left side:<BR>\n" );
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document.write( "3w^2+9w-w-3 = 0<BR>\n" );
document.write( "3w(w+3)-(w+3) = 0<BR>\n" );
document.write( "(w+3)(3w-1) = 0<BR>\n" );
document.write( "w = -3 or w = 1/3<BR>\n" );
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document.write( "Substitute to get:<BR>\n" );
document.write( "x^(1/3) = -3 or x^(1/3) = 1/3<BR>\n" );
document.write( "x = (-3)^3 or x = (1/3)^3<BR>\n" );
document.write( "x = -27 or x = 1/27<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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