document.write( "Question 145718: a worker is hired for 20 days. on the first day he makes 1 cent on the 2nd day he makes 2 cents and the pay doubles each day. What is the total pay? \n" ); document.write( "
Algebra.Com's Answer #106351 by Earlsdon(6294)\"\" \"About 
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You can look at it this way:
\n" ); document.write( "Day 1 he earns 1 cent or \"2%5E0\" cents.
\n" ); document.write( "Day 2 he earns 2 cents or \"2%5E1\" cents.
\n" ); document.write( "Day 3 he earns 4 cents or \"2%5E2\" cents.
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\n" ); document.write( "Day n he earns \"2%5E%28n-1%29\" cents.
\n" ); document.write( "The sum of these is expressed by:
\n" ); document.write( "\"S+=+2%5E0%2B2%5E2%2B2%5E3\"+...\"2%5E%28n-1%29\"=\"2%5En+-+1\" where n = the number of days worked. Here, n = 20, so...
\n" ); document.write( "\"S+=+2%5E20+-+1+=+1048575\"cents. Divide this by 100 to convert to dollars.
\n" ); document.write( "He earns a total of $10,485.75 for the 20 day's work.
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