document.write( "Question 145725: I am asked to evaluate without a calculator and I don't know where to begin?
\n" ); document.write( "log .0001
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Algebra.Com's Answer #106350 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, you could begin by recalling that: \"Log%5Bb%5D%28x%29+=+y\" means \"b%5Ey+=+x\" and that \"Log%5Bb%5D%28x%5En%29+=+n%2ALog%5Bb%5D%28x%29\" and that \"Log%5Bb%5D%28b%29+=+1\"
\n" ); document.write( "Also, \"0.0001+=+10%5E%28-4%29\"
\n" ); document.write( "Now let's see what all of this has to do with your problem:
\n" ); document.write( "\"Log%5B10%5D%28.0001%29+=+Log%5B10%5D%2810%5E%28-4%29%29\"=\"-4%2ALog%5B10%5D%2810%29+=+-4%281%29\" = \"-4\"
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