document.write( "Question 145581: In 1920, the record for a certain race was 45.9 sec. In 1950, it was 45.0 sec. Let R(t)= the record in the race and t= the number of years since 1920.
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document.write( "Find a linear function that fits the data.\r
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document.write( "R(t)=
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document.write( "(round to the nearest hundredth)\r
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document.write( "What is the predicted record for 2003?
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document.write( "(Round to the nearest 10th)\r
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document.write( "What is the predicted record for 2006?
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document.write( "(Round to the nearest 10th)\r
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #106335 by stanbon(75887) ![]() You can put this solution on YOUR website! In 1920, the record for a certain race was 45.9 sec. \n" ); document.write( "In 1950, it was 45.0 sec. \n" ); document.write( "Let R(t)= the record in the race and t= the number of years since 1920.\r \n" ); document.write( "\n" ); document.write( "Find a linear function that fits the data. \n" ); document.write( "You are given the \"y-intercept\" as (0,45.9) \n" ); document.write( "Find the slope: \n" ); document.write( "slope = (45-45.9)/30 = -0.9/30 = -0.03 \n" ); document.write( "EQUATION: \n" ); document.write( "R(t)= -0.03t + 45.9 \n" ); document.write( "---------------------------- \n" ); document.write( "What is the predicted record for 2003? \n" ); document.write( "t = 83 in 2003 \n" ); document.write( "R(83) = -0.03*83 + 45.9 \n" ); document.write( "R(83) = 43.41 \n" ); document.write( "--------------------- \n" ); document.write( "What is the predicted record for 2006? \n" ); document.write( "t = 86 in 2006 \n" ); document.write( "R(86) = -0.03*86 + 45.9 \n" ); document.write( "R(86) = 43.32 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |