document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145647>Question 145647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me with this problem  Thanks<BR>\n" );
document.write( " It said solve the linear equation using the substitution method<BR>\n" );
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document.write( "5x-2y=6<BR>\n" );
document.write( "y=2x-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106279 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-2y=6<BR>\n" );
document.write( "y=2x-3<BR>\n" );
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document.write( "Substitute 2nd into the 1st to get:<BR>\n" );
document.write( "5x -2(2x-3) = 6<BR>\n" );
document.write( "5x -4x + 6 = 6<BR>\n" );
document.write( "x = 0<BR>\n" );
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document.write( "Substitute that into y = 2x-3 to solve for \"y\":<BR>\n" );
document.write( "y = 2*0 - 3<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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