document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145639>Question 145639</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> the key in the back says the answer is 48, but i do not understand how they got there... f(n)= 5n(squared)+4n  f(3)-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #106277 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=106277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  f(n)= 5n(squared)+4n;  f(3)-9<BR>\n" );
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document.write( "Substitute 3 for n and subtract 9 from the result<BR>\n" );
document.write( "f(3) = 5(3^2) + 4(3)<BR>\n" );
document.write( "f(3) = 5(9) + 12 <BR>\n" );
document.write( "f(3) = 45 + 12 - 9 = 48\r<BR>\n" );
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document.write( " </SPAN>\n" );
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