document.write( "Question 145586This question is from textbook intermediate algebra
\n" ); document.write( ": The linear equation y = 3x – 5 graphs as a horizontal/vertical/diagonal line. I am confused by this. How do you know which it is? \n" ); document.write( "
Algebra.Com's Answer #106238 by solver91311(24713)\"\" \"About 
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Your equation is in slope-intercept form, that is: \"y=mx%2Bb\".\r
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\n" ); document.write( "\n" ); document.write( "Therefore, you know the slope for your equation.\r
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\n" ); document.write( "\n" ); document.write( "If the slope, \"m\", is:\r
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\n" ); document.write( "\n" ); document.write( "Equal to zero, you have a horizontal line.\r
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\n" ); document.write( "\n" ); document.write( "A positive number, you have a line that slants upward from left to right.\r
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\n" ); document.write( "\n" ); document.write( "A negative number, you have a line that slants downward from left to right.\r
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\n" ); document.write( "\n" ); document.write( "Undefined, as in \"x=a\" where a is any real number, then you have a vertical line. You can see why the slope is undefined by re-writing \"x=a\" as \"x%2B0y=a\" showing you that you would have to divide by zero to calculate the slope number.\r
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\n" ); document.write( "\n" ); document.write( "The visual way to do it is to plot the graph of the line. Pick any value for x, substitute that value for x in the equation, do the arithmetic to find the corresponding y value, and then plot the point (x,y) that you have just derived. Repeat the process using another value of x. Draw a line through both points.
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