document.write( "Question 145524: I am working with Inverse functions and need help find (f(g))(x) and (g(f))(x) given f(x)=log(2)x g(x)=2 to x power
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Algebra.Com's Answer #106173 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's evaluate f(g(x))\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=log%282%2C%28x%29%29\" Start with the first function\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=log%282%2C%282%5Ex%29%29\" Plug in \"g%28x%29=2%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=x%2Alog%282%2C%282%29%29\" Rewrite the right side using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=x%2A1\" Take the log base 2 of 2 to get 1. Note: \"log%28x%2C%28x%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28x%29%29=x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Let's evaluate g(f(x))\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29=2%5Ex\" Start with the second function\r
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\n" ); document.write( "\n" ); document.write( "\"g%28f%28x%29%29=2%5E%28log%282%2C%28x%29%29%29\" Plug in \"f%28x%29=log%282%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let \"y=log%282%2C%28x%29%29\". So this means that \"2%5Ey=x\" by use of the property \"log%28b%2C%28x%29%29=y\" ====> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%28f%28x%29%29=2%5Ey\" Replace \"log%282%2C%28x%29%29\" with \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%28f%28x%29%29=x\" Now replace \"2%5Ey\" with \"x\"\r
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\n" ); document.write( "\n" ); document.write( "So both f(g(x)) and g(f(x)) equal x.
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