document.write( "Question 145520: Linda headed east at 20 mph on her bicycle at 9am. Three hours later Shana headed west from the same place walking at 6 mph. What time was it that they were 164 miles apart? \n" ); document.write( "
Algebra.Com's Answer #106166 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Linda headed east at 20 mph on her bicycle at 9am. Three hours later Shana headed west from the same place walking at 6 mph. What time was it that they were 164 miles apart? \n" ); document.write( ": \n" ); document.write( "Let x = L's travel time on the bike (starting at 9am) \n" ); document.write( "Then \n" ); document.write( "(x-3) = S's walking time (starting at noon) \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "L's Dist + S's dist = 164 mi \n" ); document.write( "20x + 6(x-3) = 164 \n" ); document.write( ": \n" ); document.write( "20x + 6x - 18 = 164 \n" ); document.write( ": \n" ); document.write( "26x = 164 + 18 \n" ); document.write( "x = \n" ); document.write( "x = 7 hrs \n" ); document.write( "; \n" ); document.write( "7 hr from 9am = 4pm \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the dist of each (walking time = 4hrs) \n" ); document.write( "4(6) = 24 \n" ); document.write( "7(20) = 140 \n" ); document.write( "----------- \n" ); document.write( "total = 164 \n" ); document.write( " \n" ); document.write( " |