document.write( "Question 21975: log (base 5)x+ log (base5) (x+4)= log (base 5) 5 \n" ); document.write( "

Algebra.Com's Answer #10616 by Alwayscheerful(414) $\"\"$ $\"About$

You can put this solution on YOUR website!
Rewritten, your question equation is:
\n" ); document.write( "log[5]x +log[5]x+4=log[5]5
\n" ); document.write( "**NUMBER IN BRACKET IS THE BASE OF THE LOGARITHM**
\n" ); document.write( "I'm assuming your question is \"solve for x\"
\n" ); document.write( "Well, the first law of logarithms is:
\n" ); document.write( "log[a]x+log[a]y=log[a]xy
\n" ); document.write( "So, in your case
\n" ); document.write( " $\"x%2Ay=5\"$
\n" ); document.write( "log[5]x(x+4)=log[5]5
\n" ); document.write( "log[5]x^2+4=log[5]5
\n" ); document.write( " $\"x%5E2%2B4+=5\"$
\n" ); document.write( " $\"x%5E2=1\"$
\n" ); document.write( " $\"highlight%28x=1%29\"$
\n" ); document.write( "Hope this helps! \n" ); document.write( "

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