document.write( "Question 145483: Divide the following expression 27z+23z^2+6z^3 /(over) 2z+3 \n" ); document.write( "
Algebra.Com's Answer #106134 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"%286z%5E3+%2B+23z%5E2+%2B+27z%29+%2F+%282z+%2B+3%29\"
\n" ); document.write( "The 1st term of the answer is \"3z%5E2\" since
\n" ); document.write( "\"3z%5E2%2A%282z+%2B+3%29+=+6z%5E3+%2B+9z%5E2\"
\n" ); document.write( "\"6z%5E3+%2B+23z%5E2\"
\n" ); document.write( "\"-6z%5E3+-+9z%5E2\"
\n" ); document.write( "------------------
\n" ); document.write( "\"14z%5E2\"
\n" ); document.write( "The 2nd term of the answer is \"7z\" since
\n" ); document.write( "\"7z%2A%282z+%2B+3%29+=+14z%5E2+%2B+21z\"
\n" ); document.write( "\"14z%5E2+%2B+27z\"
\n" ); document.write( "\"-14z%5E2+-+21z\"
\n" ); document.write( "------------------
\n" ); document.write( "\"6z\" (remainder)
\n" ); document.write( "So, the complete answer is
\n" ); document.write( "\"3z%5E2+%2B+7z+%2B+%286z%2F%282z+%2B+3%29%29\"
\n" ); document.write( "You can check this by multiplying it by \"2z+%2B+3\"
\n" ); document.write( "
\n" );