document.write( "Question 145425: 1) write log7 49=2 in exponential form.\r
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document.write( "2) use the change of base formula( property 10.9) to solve for x; x=log3 90\r
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document.write( "3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3) \n" );
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Algebra.Com's Answer #106096 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1) write log7 49=2 in exponential form. \n" ); document.write( "7^2 = 49 \n" ); document.write( "------------------- \n" ); document.write( "2) use the change of base formula( property 10.9) to solve for x; x=log3 90 \n" ); document.write( "x = [log90]/[log3] \n" ); document.write( "x = 4.09590... \n" ); document.write( "-------------------- \n" ); document.write( "3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3) \n" ); document.write( "[9/(4x)] + [1/3] = [5/(2x)] \n" ); document.write( "Multiply thru by 12x to get rid of the fractions: \n" ); document.write( "27 + 4x = 30 \n" ); document.write( "4x = 3 \n" ); document.write( "x = 3/4 \n" ); document.write( "-----------------\r \n" ); document.write( "\n" ); document.write( " (x^-1=4/3) \n" ); document.write( "x = 3/4 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |