document.write( "Question 145425: 1) write log7 49=2 in exponential form.\r
\n" ); document.write( "\n" ); document.write( "2) use the change of base formula( property 10.9) to solve for x; x=log3 90\r
\n" ); document.write( "\n" ); document.write( "3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3)
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Algebra.Com's Answer #106096 by stanbon(75887)\"\" \"About 
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1) write log7 49=2 in exponential form.
\n" ); document.write( "7^2 = 49
\n" ); document.write( "-------------------
\n" ); document.write( "2) use the change of base formula( property 10.9) to solve for x; x=log3 90
\n" ); document.write( "x = [log90]/[log3]
\n" ); document.write( "x = 4.09590...
\n" ); document.write( "--------------------
\n" ); document.write( "3) solve for x: 9/(4x)+1/3=5/(2x); (x^-1=4/3)
\n" ); document.write( "[9/(4x)] + [1/3] = [5/(2x)]
\n" ); document.write( "Multiply thru by 12x to get rid of the fractions:
\n" ); document.write( "27 + 4x = 30
\n" ); document.write( "4x = 3
\n" ); document.write( "x = 3/4
\n" ); document.write( "-----------------\r
\n" ); document.write( "\n" ); document.write( " (x^-1=4/3)
\n" ); document.write( "x = 3/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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