document.write( "Question 21988: 1. 18-3y=5\r
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\n" ); document.write( "\n" ); document.write( "2. -14+9a=38\r
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\n" ); document.write( "\n" ); document.write( "3. 14r+8=32\r
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\n" ); document.write( "\n" ); document.write( "4. 37-58b=204
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Algebra.Com's Answer #10609 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The principal idea here is to isolate the variable to one side of the equation.
\n" ); document.write( "This is done by \"undoing\" (doing the opposite operation on) whatever has been done to the variable.\r
\n" ); document.write( "\n" ); document.write( "1) 18 - 3y = 5 Isolate the y-term by subtracting 18 from both sides of the equation.
\n" ); document.write( "-3y = 5-18
\n" ); document.write( "-3y = -13 Now divide both sides by -3
\n" ); document.write( "y = 13/3
\n" ); document.write( "y = 4 1/3\r
\n" ); document.write( "\n" ); document.write( "2) -14+9a = 38 Add 14 to both sides to isolate the a-term.
\n" ); document.write( "9a = 38+14
\n" ); document.write( "9a = 52 Now divide both sides by 9.
\n" ); document.write( "a = 52/9
\n" ); document.write( "a = 5 7/9\r
\n" ); document.write( "\n" ); document.write( "3) 14r+8 = 32 Subtract 8 from both sides.
\n" ); document.write( "14r = 24 Now divide both sides by 14.
\n" ); document.write( "r = 24/14
\n" ); document.write( "r = 1 5/7\r
\n" ); document.write( "\n" ); document.write( "4) 37-58b = 204 Subtract 37 from both sides.
\n" ); document.write( "-58b = 167 Now divide by -58.
\n" ); document.write( "b = -(167/58)
\n" ); document.write( "b = -2 51/58\r
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