document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21986>Question 21986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3b+8=-10b+b\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10608 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3b+8=-10b+b<BR>\n" );
document.write( "Add all like terms.<BR>\n" );
document.write( "3b+8=-9b<BR>\n" );
document.write( "Add -8 to both sides.<BR>\n" );
document.write( "3b=-9b-8<BR>\n" );
document.write( "Add 9b to both sides.<BR>\n" );
document.write( "12b=-8<BR>\n" );
document.write( "Divide both sides by 12.<BR>\n" );
document.write( "b=-8/12=-2/3\r<BR>\n" );
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document.write( "To check your answer go back and substitute -2/3 for b in the equation. </SPAN>\n" );
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