document.write( "Question 145339: which logarithmic equation is equivalent to the exponential equation below?\r
\n" ); document.write( "\n" ); document.write( "8^x=100\r
\n" ); document.write( "\n" ); document.write( "a. x=log8 100\r
\n" ); document.write( "\n" ); document.write( "b. x=log100 8\r
\n" ); document.write( "\n" ); document.write( "c. 100=logx 8\r
\n" ); document.write( "\n" ); document.write( "b. 8=logx 100
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Algebra.Com's Answer #106012 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"8%5Ex=100+\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%288%5Ex%29%29=log%2810%2C%28100%29%29+\" Take the log base 10 of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Alog%2810%2C%288%29%29=log%2810%2C%28100%29%29+\" Rewrite the left side using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%2810%2C%28100%29%29%2Flog%2810%2C%288%29%29+\" Divide both sides by \"log%2810%2C%288%29%29\" to isolate x.\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%288%2C%28100%29%29\" Use the change of base formula to simplify.\r
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\n" ); document.write( "\n" ); document.write( "So \"8%5Ex=100+\" is equivalent to \"x=log%288%2C%28100%29%29\"
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