document.write( "Question 145312This question is from textbook
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document.write( ": Lois leaves at 8:00am traveling at 35 mph, traveling in the opposite direction,Clark leaves at 815 a.m. traveling at 40 mph. At what time will they be 140 miles apart \n" );
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Algebra.Com's Answer #105980 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 35*x+40(x-.25)=140 \n" ); document.write( "35x+40x-10=140 \n" ); document.write( "75x=150 \n" ); document.write( "x=150/75 \n" ); document.write( "x=2 hour after Lois leaves they will be 140 miles apart. \n" ); document.write( "proof: \n" ); document.write( "35*2+40(2-.25)=140 \n" ); document.write( "70+40*1.75=140 \n" ); document.write( "70+70=140 \n" ); document.write( "140=140 \n" ); document.write( " \n" ); document.write( " |