document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145304>Question 145304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an alloy of tin and  copper contains 14 pounds of tin and 26 pounds of copper.<BR>\n" );
document.write( "a second alloy of tin and copper contains 8 pounds of tin and 24 pounds of copper.  How many pounds of each alloy must be taken to form a third alloy<BR>\n" );
document.write( "containing 15 pounds of tin and 35 pounds of copper. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105975 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n alloy of tin and copper contains 14 pounds of tin and 26 pounds of copper.<BR>\n" );
document.write( "a second alloy of tin and copper contains 8 pounds of tin and 24 pounds of copper. How many pounds of each alloy must be taken to form a third alloy<BR>\n" );
document.write( "containing 15 pounds of tin and 35 pounds of copper.<BR>\n" );
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document.write( "Solve this using the decimal value of %tin:<BR>\n" );
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document.write( "Find the per cent tin in the 1st alloy:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14%2F%28%2814%2B26%29%29 ALIGN=MIDDLE  ALT=\"14%2F%28%2814%2B26%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .35<BR>\n" );
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document.write( "Find the per cent tin in the 2nd alloy<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2F%28%288%2B24%29%29 ALIGN=MIDDLE  ALT=\"8%2F%28%288%2B24%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .25<BR>\n" );
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document.write( "Find the per cent tin in the resulting alloy<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2F%28%2815%2B35%29%29 ALIGN=MIDDLE  ALT=\"15%2F%28%2815%2B35%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .30<BR>\n" );
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document.write( "Let x = amt of the 1st alloy required<BR>\n" );
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document.write( "The resulting total amt is (15 + 35) = 50 lb, therefore:<BR>\n" );
document.write( "(50-x) = amt of the 2nd equation<BR>\n" );
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document.write( "The per cent tin equation:<BR>\n" );
document.write( ".35x + .25(50-x) = .3(50)<BR>\n" );
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document.write( ".35x + 12.5 - .25x = 15<BR>\n" );
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document.write( ".35x - .25x = 15 - 12.5<BR>\n" );
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document.write( ".10x = 2.5<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.5%2F.1 ALIGN=MIDDLE  ALT=\"2.5%2F.1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 25 lb of alloy #1<BR>\n" );
document.write( "and<BR>\n" );
document.write( "50 - 25 = 25 lb of alloy #2<BR>\n" );
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document.write( "Check solution using %tin equation<BR>\n" );
document.write( ".35(25) + .25(25) = .30(50)<BR>\n" );
document.write( "8.75 + 6.25 =15 </SPAN>\n" );
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