document.write( "Question 145261: Tutor please help me?\r
\n" ); document.write( "\n" ); document.write( "Simplify log3 64/log3 16
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Algebra.Com's Answer #105938 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Simplify log3 64/log3 16
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\n" ); document.write( "Using loga b = (logc b)/(logc a) you have:\r
\n" ); document.write( "\n" ); document.write( "[(log2 64)/(log2 3)] / [(log2 16)/(log2 3]\r
\n" ); document.write( "\n" ); document.write( "The log2 3 factors cancel and you have:\r
\n" ); document.write( "\n" ); document.write( "= [ 6/1] / [4/1]\r
\n" ); document.write( "\n" ); document.write( "= 6/4 \r
\n" ); document.write( "\n" ); document.write( "= 3/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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