document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145245>Question 145245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The flag jamie bought has a perimter of 75 feet<BR>\n" );
document.write( "the width of the flag is 4 feet less than 2 times the length.<BR>\n" );
document.write( "What are the measurements </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105918 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2W + 2L = 75<BR>\n" );
document.write( "W = 2L-4<BR>\n" );
document.write( "Substitute for W<BR>\n" );
document.write( "2(2L-4) + 2L = 75<BR>\n" );
document.write( "4L-8 +2L = 75<BR>\n" );
document.write( "6L = 83<BR>\n" );
document.write( "L = 13 5/6 feet, or 13' 10\"<BR>\n" );
document.write( "W = 2L-4 = (83/3)-4<BR>\n" );
document.write( "W = 71/3<BR>\n" );
document.write( "W = 23 2/3 feet, or 23' 8\"<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );