document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21924>Question 21924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sue leaves home at 9 a.m. bicycling at a rate of 28 mi/h. Two hours later, Joe leaves driving at the rate of 48 mi/h. At what time will Joe catch up with Sue? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10589 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t be the time<BR>\n" );
document.write( "28(t+2)=48t<BR>\n" );
document.write( "28t+56=48t<BR>\n" );
document.write( "20t=56<BR>\n" );
document.write( "t=2.8<BR>\n" );
document.write( "9+2.8=11.8<BR>\n" );
document.write( "Hence, Joe will catch sue at 11.8 am 2.8 hours from where sue left </SPAN>\n" );
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