document.write( "Question 145157: I have a problem setting up the equation for these 2 word problems. Any help would be greatly appreciated. \r
\n" ); document.write( "\n" ); document.write( "The instructions are:
\n" ); document.write( "For questions 5 and 6, recall that, when interest is compounded continuously, the balance in an account after t years is given by
\n" ); document.write( "A = Pert,
\n" ); document.write( "where P is the initial investment and r is the interest rate. \r
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\n" ); document.write( "\n" ); document.write( "5. Maya has deposited $600 in an account that pays 5.64% interest, compounded continuously. How long will it take for her money to double? \r
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\n" ); document.write( "\n" ); document.write( "6. Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs?\r
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Algebra.Com's Answer #105881 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
see this --> http://www.moneychimp.com/articles/finworks/continuous_compounding.htm\r
\n" ); document.write( "\n" ); document.write( "Given \"A=+Pe%5E%28rt%29+\"\r
\n" ); document.write( "\n" ); document.write( "Maya has deposited $600 in an account that pays 5.64% interest, compounded continuously. How long will it take for her money to double? \r
\n" ); document.write( "\n" ); document.write( "\"1200+=+600e%5E%280.0564t%29\"
\n" ); document.write( "\"2+=+e%5E%280.0564t%29\"
\n" ); document.write( "\"ln2+=+0.0564t+\"
\n" ); document.write( "\"ln2%2F+%280.0564%29+=+t+\"
\n" ); document.write( "\"12.29+=+t+\"\r
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\n" ); document.write( "\n" ); document.write( "Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs?\r
\n" ); document.write( "\n" ); document.write( "\"A+=+6000e%5E%280.06t%29+\"
\n" ); document.write( "\"A=+6000e%5E%280.06%29\"
\n" ); document.write( "\"A+=+6371\" after 1 year\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+6000e%5E%280.06t%29+\"
\n" ); document.write( "\"A=+6000e%5E%280.06+%2A+2%29\"
\n" ); document.write( "\"A+=+6765\" after 2 years
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