document.write( "Question 145216This question is from textbook
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\n" ); document.write( "\n" ); document.write( "14. (2 pts) How many different ways are there for an admissions officer to select a group of 7 college candidates from a group of 19 applicants for an interview? 19 * 7 at a time = 19*18*17*16*15*14*13
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Algebra.Com's Answer #105880 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that order does not matter. \r
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\n" ); document.write( "\n" ); document.write( "Since order does not matter, we must use the combination formula:\r
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\n" ); document.write( "\n" ); document.write( "\"n%21%2F%28n-r%29%21r%21\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"19%21%2F%2819-7%29%217%21\" Plug in \"n=19\" and \"r=7\"\r
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\n" ); document.write( "\n" ); document.write( "\"19%21%2F12%217%21\" Subtract \"19-7\" to get 12\r
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\n" ); document.write( "\n" ); document.write( "Expand 19!
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\n" ); document.write( "\n" ); document.write( "Expand 12!
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\n" ); document.write( "\n" ); document.write( "\"%2819%2A18%2A17%2A16%2A15%2A14%2A13%29%2F7%21\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Expand 7!
\n" ); document.write( "\"%2819%2A18%2A17%2A16%2A15%2A14%2A13%29%2F%287%2A6%2A5%2A4%2A3%2A2%2A1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"253955520%2F%287%2A6%2A5%2A4%2A3%2A2%2A1%29\" Multiply 19*18*17*16*15*14*13 to get 253,955,520\r
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\n" ); document.write( "\n" ); document.write( "\"253955520%2F5040\" Multiply 7*6*5*4*3*2*1 to get 5,040\r
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\n" ); document.write( "\n" ); document.write( "\"50388\" Now divide\r
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\n" ); document.write( "\n" ); document.write( "So 19 choose 7 (where order doesn't matter) yields 50,388 unique combinations
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