document.write( "Question 145207: Hello (again),
\n" ); document.write( "Please disregard the first question sent to you from (kenronda@sover.net).\r
\n" ); document.write( "\n" ); document.write( "After thinking about my question I relized it was flawed in a few ways.
\n" ); document.write( "Also, I mis-quoted the text I was working from. (sorry mr. text)\r
\n" ); document.write( "\n" ); document.write( "If you would allow me to re-phrase my question:
\n" ); document.write( "Problem: (solve: 2cosx + sin2x = 0)
\n" ); document.write( "I used the Double-Angle Identity to make (sin2x) ---> (2sinxcosx)\r
\n" ); document.write( "\n" ); document.write( "Can I view a term that looks like this: (2sinxcosx)
\n" ); document.write( "as: (2)(sinx)(cosx) -----> (sinx)(2)(cosx) ?????????\r
\n" ); document.write( "\n" ); document.write( "If this is legal it would let me Factor out the (2)(cosx) from the
\n" ); document.write( "original problem and solve each Factor for the Solution Set.\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help-- ken b \r
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Algebra.Com's Answer #105879 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
Ken, I saw that first post and could not get it past 2cosx (1 + sinx) \r
\n" ); document.write( "\n" ); document.write( "You also asked for a good source for identities. I like this one. http://mathforum.org/dr.math/faq/formulas/faq.trig.html \n" ); document.write( "

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