document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145139>Question 145139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please help me with a few problems on cramer's rule? I want to know if I'm doing it right.Thank you so much in advance.<BR>\n" );
document.write( "1)2x + 5y = 3<BR>\n" );
document.write( "   x + 4y = 2\r<BR>\n" );
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document.write( "2)x + 2y = 4<BR>\n" );
document.write( " 3x - 2y = -12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105844 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This site explains Cramer's rule in detail:<BR>\n" );
document.write( "http://www.purplemath.com/modules/cramers.htm\r<BR>\n" );
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document.write( "1)2x + 5y = 3<BR>\n" );
document.write( "   x + 4y = 2\r<BR>\n" );
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document.write( "Determinant of D:<BR>\n" );
document.write( "2 5<BR>\n" );
document.write( "1 4<BR>\n" );
document.write( "equals (2*4)-(1*5) = 8-5 = 3<BR>\n" );
document.write( "Determinant of D(x):<BR>\n" );
document.write( "3 5<BR>\n" );
document.write( "2 4<BR>\n" );
document.write( "equals (3*4)-(2*5) = 12-10 = 2\r<BR>\n" );
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document.write( "x = D(x)/D = 2/3<BR>\n" );
document.write( "Determinant of D(y):<BR>\n" );
document.write( "2 3<BR>\n" );
document.write( "1 2<BR>\n" );
document.write( "equals (2*2)-(1*3) = 4-3 = 1<BR>\n" );
document.write( "y = D(y)/D = 1/3\r<BR>\n" );
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document.write( "2)x + 2y = 4<BR>\n" );
document.write( " 3x - 2y = -12\r<BR>\n" );
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document.write( "Determinant of D:<BR>\n" );
document.write( "1 2<BR>\n" );
document.write( "3 -2<BR>\n" );
document.write( "equals (1*(-2))-(3*2) = -2-6 = -8<BR>\n" );
document.write( "Determinant of D(x):<BR>\n" );
document.write( "4    2<BR>\n" );
document.write( "-12 -2<BR>\n" );
document.write( "equals (4*(-2))-((-12)*2) = -8-(-24) = 16\r<BR>\n" );
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document.write( "x = D(x)/D = 16/(-8) = -2<BR>\n" );
document.write( "Determinant of D(y):<BR>\n" );
document.write( "1 4<BR>\n" );
document.write( "3 -12<BR>\n" );
document.write( "equals (1*(-12))-(4*3) = -12-12 = -24<BR>\n" );
document.write( "y = D(y)/D = -24/(-8) = 3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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