document.write( "Question 145132: Please help me solve by taking roots of of both sides:\r
\n" ); document.write( "\n" ); document.write( "y^2=16\r
\n" ); document.write( "\n" ); document.write( "(x-3)^2=25
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Algebra.Com's Answer #105822 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"y%5E2+=+16\" Take the square root of both sides.
\n" ); document.write( "\"sqrt%28y%5E2%29+=+sqrt%2816%29\"
\n" ); document.write( "\"y+=+4\" or \"y+=+-4\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+=+25\" Take the square root of both sides.
\n" ); document.write( "\"sqrt%28%28x-3%29%5E2%29+=+sqrt%2825%29\"
\n" ); document.write( "\"x-3+=+5\" or \"x-3+=+-5\" Add 3 to both sides in each case.
\n" ); document.write( "\"x+=+3%2B5\" or \"x+=+3-5\"
\n" ); document.write( "\"x+=+8\" or \"x+=+-2\"
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