document.write( "Question 145109: A personn invested 10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income form the smaller part. what is the smaller part of the the investment? \n" ); document.write( "
Algebra.Com's Answer #105805 by checkley77(12844)\"\" \"About 
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.06X=.05(10,000-X)+160
\n" ); document.write( ".06X=500-.05X+160
\n" ); document.write( ".06X+.05X=660
\n" ); document.write( ".11X=660
\n" ); document.write( "X=660/.11
\n" ); document.write( "X=$6,000 INVESTED @ 6%.
\n" ); document.write( "10,000-6,000=4,000 INVESTED @ 5%.
\n" ); document.write( "PROOF
\n" ); document.write( ".06*6,000=.05*4,000+160
\n" ); document.write( "360=200+160
\n" ); document.write( "360=360
\n" ); document.write( "
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