document.write( "Question 145099: please help??
\n" ); document.write( "it says solve by completing the square:\r
\n" ); document.write( "\n" ); document.write( "x^2+8x+3=0\r
\n" ); document.write( "\n" ); document.write( "x^2+4x+1=0\r
\n" ); document.write( "\n" ); document.write( "x^2-5x+=11
\n" ); document.write( "

Algebra.Com's Answer #105783 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Read this -->http://www.purplemath.com/modules/sqrquad.htm\r
\n" ); document.write( "\n" ); document.write( "Now let's solve the first one using that method. The others are for you\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B8x%2B3=0\"\r
\n" ); document.write( "\n" ); document.write( "Move the loose number over to the other side.
\n" ); document.write( "\"x%5E2%2B8x=-3\"\r
\n" ); document.write( "\n" ); document.write( "Divide through by whatever is multiplied on the squared term.
\n" ); document.write( "In this case that is 1, so we are done.\r
\n" ); document.write( "\n" ); document.write( "Take half of the coefficient (don't forget the sign!) of the x-term, and square it. Add this square to both sides of the equation.
\n" ); document.write( "\"8%2A%281%2F2%29\" = \"4\"
\n" ); document.write( "\"4%5E2\"=\"16\"
\n" ); document.write( "\"x%5E2%2B8x+%2B+16=-3+%2B+16\"\r
\n" ); document.write( "\n" ); document.write( "Convert the left-hand side to squared form, and simplify the right-hand side. (This is where you use that sign that you kept track of earlier.)
\n" ); document.write( "\"%28x%2B4%29%5E2+=13\"\r
\n" ); document.write( "\n" ); document.write( "Square-root both sides, remembering the \"±\" on the right-hand side. Simplify as necessary.
\n" ); document.write( "\"x%2B4+=+%2B-sqrt%2813%29\"\r
\n" ); document.write( "\n" ); document.write( "Solve for \"x =\".
\n" ); document.write( "\"x+=+%2B-sqrt%2813%29+-+4+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%2813%29+-+4\" and \"x+=+-sqrt%2813%29+-+4\"
\n" ); document.write( "
\n" );