document.write( "Question 144967: solve the following systems of linear equations using the elimination method show your solution as an ordered triple
\n" ); document.write( "x-2y+3=-4
\n" ); document.write( "3x+y-z=0
\n" ); document.write( "2x+3y-5z=1 \n" ); document.write( "
Algebra.Com's Answer #105780 by seema230480(3)\"\" \"About 
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x-2y+3=-4--------------1
\n" ); document.write( "3x+y-z=0--------------2
\n" ); document.write( "2x+3y-5z=1------------3\r
\n" ); document.write( "\n" ); document.write( "From 2, z=3x+y
\n" ); document.write( "So 3 becomes, 2x+3y-5(3x+y)=1
\n" ); document.write( "Solving the above we get, -13x-2y=1---------4
\n" ); document.write( "From 1 we have, x-2y=-7\r
\n" ); document.write( "\n" ); document.write( "Solving 1 and 4 we have
\n" ); document.write( "-13x-2y=1-----------4
\n" ); document.write( "x-2y=-7-------------5\r
\n" ); document.write( "\n" ); document.write( "Multiply 13 on both sides of 5, we have now 13x-26y=-91\r
\n" ); document.write( "\n" ); document.write( "Subtracting one from the other, we have
\n" ); document.write( "13x-26y=-91
\n" ); document.write( "-13x-2y=1
\n" ); document.write( "-------------
\n" ); document.write( "0-28y=-90
\n" ); document.write( "-----------
\n" ); document.write( "y=90/28=45/14
\n" ); document.write( "x=-7+2*45/14
\n" ); document.write( "x=(-49+45)/7=-4/7\r
\n" ); document.write( "\n" ); document.write( "z=3*(-4/7)+45/14=3/2 \n" ); document.write( "
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