document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145088>Question 145088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Xander and Ella pool their loose change to buy snacks on their coffee break. One day, they spend $1.85 on 1 carton of milk, 2 donuts, and 1 cup of coffee. The next day, they spend $2.30 on 3 donuts and 2 cups of coffee. The third day, they bought 1 carton of milk, 1 donut, and 2 cups of coffee and spent $1.75. On the fourth day, They have a total of $1.80 left. Is this enough to buy 2 cartons of milk and 2 donuts?\r<BR>\n" );
document.write( "\n" );
document.write( "equation #1________<BR>\n" );
document.write( "equation #2________<BR>\n" );
document.write( "Equation #3 _______<BR>\n" );
document.write( "milk cost ______<BR>\n" );
document.write( "Donut Cost _____<BR>\n" );
document.write( "Coffee Cost_____<BR>\n" );
document.write( "4th day cost______<BR>\n" );
document.write( "available $1.80<BR>\n" );
document.write( "yes or no________\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I am finding this question VERY hard!! Please help me :) <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105774 by </B><A HREF=/tutors/aboutme.mpl?userid=seema230480><B>seema230480(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=seema230480><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's denote Milk carton by M,<BR>\n" );
document.write( "Doughnuts by D<BR>\n" );
document.write( "Coffee by C\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "First Equation formation:<BR>\n" );
document.write( "they spend $1.85 on 1 carton of milk, 2 donuts, and 1 cup of coffee<BR>\n" );
document.write( "So with the above said first equation becomes: 1M+2D+1C=1.85\r<BR>\n" );
document.write( "\n" );
document.write( "Second Equation formation:<BR>\n" );
document.write( "next day, they spend $2.30 on 3 donuts and 2 cups of coffee.<BR>\n" );
document.write( "So with the above said second equation becomes: 3D+2C=2.30\r<BR>\n" );
document.write( "\n" );
document.write( "Third Equation formation:<BR>\n" );
document.write( "third day, they bought 1 carton of milk, 1 donut, and 2 cups of coffee and spent $1.75<BR>\n" );
document.write( "So with the above said second equation becomes: \r<BR>\n" );
document.write( "\n" );
document.write( "Now we solve these 3 equations:<BR>\n" );
document.write( "1M+2D+1C=1.85-------------------------->eqn 1<BR>\n" );
document.write( "3D+2C=2.30       ---------------------------->eqn 2<BR>\n" );
document.write( "1M+1D+2C=1.75--------------------------->eqn 3\r<BR>\n" );
document.write( "\n" );
document.write( "Look for similar number of M's, D's or C's in any 2 equations. we see that Equation 1 and 3 have same numbers of M's that is \"1M\"<BR>\n" );
document.write( "Now subtract Equation 1 from 3 or 3 from 1 whichever you find easy.<BR>\n" );
document.write( "Let's say we subtract 3 from 1, so we get:\r<BR>\n" );
document.write( "\n" );
document.write( "1M+2D+1C=1.85<BR>\n" );
document.write( "1M+1D+2C=1.75<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "(1M-1M)+(2D-1D)+(1C-2C)=(1.85-1.75)<BR>\n" );
document.write( "implies 0M+1D-1C=0.1---------------------->eqn 4\r<BR>\n" );
document.write( "\n" );
document.write( "Now we will try to solve eqn 2 and eqn 4.<BR>\n" );
document.write( "3D+2C=2.30       ---------------------------->eqn 2<BR>\n" );
document.write( "1D-1C=0.1---------------------->eqn 4<BR>\n" );
document.write( "From eqn 4 we have D=0.1+C------>eqn 5<BR>\n" );
document.write( "Now putting this value of D in eqn 2, we have<BR>\n" );
document.write( "3(0.1+C)+2C=2.30<BR>\n" );
document.write( "implies 0.3+3C+2C=2.30<BR>\n" );
document.write( "implies 5C=2.30-0.3<BR>\n" );
document.write( "implies 5C=2<BR>\n" );
document.write( "implies C=0.4\r<BR>\n" );
document.write( "\n" );
document.write( "Now from eqn 5, D=0.1+0.4=0.5<BR>\n" );
document.write( "So, D=0.5\r<BR>\n" );
document.write( "\n" );
document.write( "From eqn 1, M=1.85-2D-1C<BR>\n" );
document.write( "implies M=1.85-2*0.5-0.4<BR>\n" );
document.write( "implies M=1.85-1-.0.4<BR>\n" );
document.write( "So, M=0.45\r<BR>\n" );
document.write( "\n" );
document.write( "Fourth day cost: 2M+2D=2*0.45+2*0.5<BR>\n" );
document.write( "implies fourth day cost=0.9+1=1.9\r<BR>\n" );
document.write( "\n" );
document.write( "So they won't be able to get 2 Dougnuts and 2 cartons of Milk with $1.8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );