document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=145088>Question 145088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Xander and Ella pool their loose change to buy snacks on their coffee break. One day, they spend $1.85 on 1 carton of milk, 2 donuts, and 1 cup of coffee. The next day, they spend $2.30 on 3 donuts and 2 cups of coffee. The third day, they bought 1 carton of milk, 1 donut, and 2 cups of coffee and spent $1.75. On the fourth day, They have a total of $1.80 left. Is this enough to buy 2 cartons of milk and 2 donuts?\r<BR>\n" );
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document.write( "equation #1________<BR>\n" );
document.write( "equation #2________<BR>\n" );
document.write( "Equation #3 _______<BR>\n" );
document.write( "milk cost ______<BR>\n" );
document.write( "Donut Cost _____<BR>\n" );
document.write( "Coffee Cost_____<BR>\n" );
document.write( "4th day cost______<BR>\n" );
document.write( "available $1.80<BR>\n" );
document.write( "yes or no________\r<BR>\n" );
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document.write( "I am finding this question VERY hard!! Please help me :) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105770 by </B><A HREF=/tutors/aboutme.mpl?userid=faceoff57><B>faceoff57(108)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=faceoff57><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=faceoff57><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1m + 2d + 1c = 1.85<BR>\n" );
document.write( "3d + 2c = 2.30<BR>\n" );
document.write( "1m + 1d + 2c = 1.75\r<BR>\n" );
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document.write( "1m + 2d + 1c = 1.85<BR>\n" );
document.write( "-(1m + 1d + 2c = 1.75)\r<BR>\n" );
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document.write( "1m + 2d + 1c = 1.85<BR>\n" );
document.write( "-1m - 1d - 2c = -1.75<BR>\n" );
document.write( "d - c = .10<BR>\n" );
document.write( "d = c + .10\r<BR>\n" );
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document.write( "3d + 2c = 2.30<BR>\n" );
document.write( "3(c + .10) + 2c = 2.30<BR>\n" );
document.write( "3c + .30 + 2c = 2.30<BR>\n" );
document.write( "5c + .30 = 2.30<BR>\n" );
document.write( "5c = 2.30 - .30<BR>\n" );
document.write( "5c = 2.00<BR>\n" );
document.write( "c = .40\r<BR>\n" );
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document.write( "3d + 2c = 2.30<BR>\n" );
document.write( "3d + 2(.40) = 2.30<BR>\n" );
document.write( "3d + .80 = 2.30<BR>\n" );
document.write( "3d = 2.30 - .80<BR>\n" );
document.write( "3d = 1.50<BR>\n" );
document.write( "d = .50\r<BR>\n" );
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document.write( "1m + 1d + 2c = 1.75<BR>\n" );
document.write( "1m + 1(.50) + 2(.40) = 1.75<BR>\n" );
document.write( "1m + .50 + .80 = 1.75<BR>\n" );
document.write( "1m + 1.30 = 1.75<BR>\n" );
document.write( "1m = 1.75 - 1.30<BR>\n" );
document.write( "1m = .45\r<BR>\n" );
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document.write( "cup of coffee = .40<BR>\n" );
document.write( "donut = .50<BR>\n" );
document.write( "carton of milk = .45\r<BR>\n" );
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document.write( "2 cartons of milk is .90 and 2 donuts is $1.00. The total equalling $1.90. $1.80 is not enough. They are short .10. \r<BR>\n" );
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