document.write( "Question 145040: \"x%5E2-4y%5E2%2B2x-32y-67=0\"
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Algebra.Com's Answer #105741 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
I need this equation in y form please and thank you
\n" ); document.write( "and please show all the steps of how to get y by itself.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4y%5E2%2B2x-32y-67=0\"
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document.write( "Rearrange so that the \"y%5E2\" term is first,\r\n" );
document.write( "then the \"y\" term, then the others:\r\n" );
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document.write( "\"-4y%5E2-32y%2Bx%5E2%2B2x-67=0\"\r\n" );
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document.write( "Group the last three terms on the left:\r\n" );
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document.write( "\"-4y%5E2-32y%2B%28x%5E2%2B2x-67%29=0\"\r\n" );
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document.write( "It will be easier if we multiply every term\r\n" );
document.write( "through by -1, so it will begin with a\r\n" );
document.write( "positive term:\r\n" );
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document.write( "\"4y%5E2%2B32y-%28x%5E2%2B2x-67%29=0\"\r\n" );
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document.write( "Now we will use the quadratic formula with\r\n" );
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document.write( "\"A+=+4\", \"B=32\", \"C+=+-%28x%5E2%2B2x-67%29\"\r\n" );
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document.write( "\"y+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%28+32%5E2-4%284%29%28-%28x%5E2%2B2x-67%29%29+%29%29%2F%282%284%29%29+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%281024-16%28-x%5E2-2x%2B67%29+%29%29%2F8+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%281024%2B16x%5E2%2B32x-1072%29+%29%2F8+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%2816x%5E2%2B32x-48%29+%29%2F8+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%2816%28x%5E2%2B2x-3%29%29+%29%2F8+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+sqrt%2816%29sqrt%28x%5E2%2B2x-3%29%29+%2F8+\"\r\n" );
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document.write( "\"y+=+%28-32+%2B-+4sqrt%28x%5E2%2B2x-3%29%29+%2F8+\"\r\n" );
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document.write( "\"y+=+%284%28-8+%2B-+sqrt%28x%5E2%2B2x-3%29%29%29+%2F8+\"\r\n" );
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document.write( "\"y+=+%28-8+%2B-+sqrt%28x%5E2%2B2x-3%29%29+%2F2+\"\r\n" );
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document.write( "Edwin
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