document.write( "Question 144879This question is from textbook
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\n" ); document.write( "\n" ); document.write( "6. (4 pts)
\n" ); document.write( "1000 tickets for prizes are sold for $2 each. Seven prizes will be awarded – one for $400, one for $200, and five for $50. Steven purchases one of the tickets.
\n" ); document.write( "400(1/1000) + 200(1/1000) + 50(5/1000) – 2(993/1000) = -1.14
\n" ); document.write( "a) Find the expected value expected value is -$1.14
\n" ); document.write( "b) Find the fair price of the ticket. ?????
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Algebra.Com's Answer #105709 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
You have part a done correctly. Steven (or anyone else for that matter) can expect to lose -$1.14 for every $2.00 spent. In other words, the game is rigged (way, way, way) in favor of the house.\r
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\n" ); document.write( "\n" ); document.write( "The fair price for a ticket is that price that would make the expected value be zero. So, reuse your expected value formula, this time using a variable \"P%5Bf%5D\" in place of the $2 in your previous calculation and set it equal to 0:\r
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\n" ); document.write( "\n" ); document.write( "Solve for \"P%5Bf%5D\" and you have your fair price.
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