document.write( "Question 21903: one number exceeds another number by 2 and the product of the two numbers is 143. Find the numbers \n" ); document.write( "

Algebra.Com's Answer #10570 by algebrapro18(249) $\"\"$ $\"About$

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well create a system of equations to represent the situation
\r
\n" ); document.write( "\n" ); document.write( "x+2=y
\n" ); document.write( "xy=143
\r
\n" ); document.write( "\n" ); document.write( "now solve the system
\r
\n" ); document.write( "\n" ); document.write( "xy=143
\n" ); document.write( "x(x+2)=143
\n" ); document.write( "x^2+2x=143
\n" ); document.write( "x^2+2x-143=0
\n" ); document.write( "(x+13)(x-11)=0
\n" ); document.write( "x+13=0
\n" ); document.write( "x = -13
\r
\n" ); document.write( "\n" ); document.write( "x-11 = 0
\n" ); document.write( "x = 11
\r
\n" ); document.write( "\n" ); document.write( "y=x+2
\n" ); document.write( "y=-13+2
\n" ); document.write( "y=-11
\r
\n" ); document.write( "\n" ); document.write( "y=x+2
\n" ); document.write( "y=11+2
\n" ); document.write( "y=13
\n" ); document.write( "

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