document.write( "Question 144954: Test at the 0.01 level the statement that 55% of those families who plan to purchase a vacation residence in Florida want a condominium. The null hypothesis is p = 0.55 and the alternate is p 0.55. A random sample of 400 families who planned to buy a vacation residence revealed that 228 families want a condominium. What decision should be made regarding the null hypothesis? The Z critical is 2.576 and the test statistic calculates to : (228/400 - .55)/ sqrt(.55(.45)/400) = 0.8.
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document.write( " A) Do not reject it
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document.write( " B) Reject it
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document.write( " C) Cannot accept nor reject it based on the information given
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document.write( " D) None of the above
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document.write( "
Algebra.Com's Answer #105688 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Test at the 0.01 level the statement that 55% of those families who plan to purchase a vacation residence in Florida want a condominium. The null hypothesis is p = 0.55 and the alternate is p 0.55. A random sample of 400 families who planned to buy a vacation residence revealed that 228 families want a condominium. What decision should be made regarding the null hypothesis? The Z critical is 2.576 and the test statistic calculates to : (228/400 - .55)/ sqrt(.55(.45)/400) = 0.8. \n" ); document.write( "A) Do not reject it \n" ); document.write( "B) Reject it \n" ); document.write( "C) Cannot accept nor reject it based on the information given \n" ); document.write( "D) None of the above \n" ); document.write( "-------------- \n" ); document.write( "Since the test statistic is 0.8 < 2.576, Fail to reject Ho. \n" ); document.write( "Answer: A \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |