document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21905>Question 21905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and 12 times its reciprocal is -7.  Find the numbers.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10568 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first create an equation representing the situation <br>\r<BR>\n" );
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document.write( "x+12/x=-7<br>\r<BR>\n" );
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document.write( "now multiply both sides of the equation by x to clear the fraction <br>\r<BR>\n" );
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document.write( "x^2+12 = -7x<br>\r<BR>\n" );
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document.write( "now solve<br>\r<BR>\n" );
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document.write( "x^2+7x+12=0<BR>\n" );
document.write( "(x+3)(x+4)<br>\r<BR>\n" );
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document.write( "x+3=0 x+4=0 <br>\r<BR>\n" );
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document.write( "x= -3 and -4<br>\r<BR>\n" );
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document.write( "checking<br>\r<BR>\n" );
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document.write( "-3-12/3=-7<BR>\n" );
document.write( "-3+-4=-7<BR>\n" );
document.write( "-7=-7<br>\r<BR>\n" );
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document.write( "-4-12/-4=-7<BR>\n" );
document.write( "-4+-3=-7<BR>\n" );
document.write( "-7=-7 </SPAN>\n" );
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