document.write( "Question 144914: Solve:\r
\n" ); document.write( "\n" ); document.write( "If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t - 16t2. Find the number of seconds the object is in the air before it hits the ground.
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Algebra.Com's Answer #105625 by josmiceli(19441)\"\" \"About 
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\"h+=+64t+-+16t%5E2\"
\n" ); document.write( "If you substitute \"t=0\", you see that \"h=0\"
\n" ); document.write( "That is the time and the height when the object is
\n" ); document.write( "released.
\n" ); document.write( "What you want to find is another time when \"h=0\",
\n" ); document.write( "and that will be the time when the object has come
\n" ); document.write( "back to earth, so
\n" ); document.write( "\"64t+-+16t%5E2+=+0\"
\n" ); document.write( "\"t%2864+-+16t%29+=+0\"
\n" ); document.write( "This equation is true if either of the factors, \"t\", or
\n" ); document.write( "\"64+-+16t\" is zero
\n" ); document.write( "\"64+-+16t+=+0\"
\n" ); document.write( "\"t+=+4\"
\n" ); document.write( "So the object is in the air 4 sec before it hits the ground
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