document.write( "Question 144915: Solve:\r
\n" ); document.write( "\n" ); document.write( "If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t - 16t2. Find the number of seconds the object is in the air before it hits the ground. \r
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Algebra.Com's Answer #105620 by nabla(475)\"\" \"About 
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0=64t-16t^2
\n" ); document.write( "0=-16t(t-4)\r
\n" ); document.write( "\n" ); document.write( "Implies t=0 or t=4.\r
\n" ); document.write( "\n" ); document.write( "We exclude t=0, leaving t=4 the only solution.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "64(4)-16(4^2)=256-256=0.
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