document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144919>Question 144919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Steve traveled 600 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105602 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "600=RT OR R=600/T<BR>\n" );
document.write( "600=(R+20)(T-1) MULTIPLY THE 2 RIGHT TERMS.<BR>\n" );
document.write( "600=RT+20T-R-20 REPLACE RT WITH 600 & R WITH 600/T<BR>\n" );
document.write( "600=600+20T-600/T-20<BR>\n" );
document.write( "0=20T-600/T-20<BR>\n" );
document.write( "20T-600/T=20 <BR>\n" );
document.write( "(20T^2-600)/T=20<BR>\n" );
document.write( "20T^2-600=20T<BR>\n" );
document.write( "20T^2-20T-600=0<BR>\n" );
document.write( "20(T^2-T-30)=0<BR>\n" );
document.write( "20(T-6)(T+5)=0<BR>\n" );
document.write( "T-6=0<BR>\n" );
document.write( "T=6 HOURS FOR THE ORIGINAL TRIP.<BR>\n" );
document.write( "600=R*6<BR>\n" );
document.write( "600=6R<BR>\n" );
document.write( "R=600/6<BR>\n" );
document.write( "R=100 MPH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "600=(100+20)(6-1)<BR>\n" );
document.write( "600=120*5<BR>\n" );
document.write( "600=600<BR>\n" );
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