document.write( "Question 144782: Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
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Algebra.Com's Answer #105554 by ankor@dixie-net.com(22740)\"\" \"About 
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Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle
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\n" ); document.write( "Let s = speed of his vehicle
\n" ); document.write( "then
\n" ); document.write( "(s+10) = the faster speed
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "Actual time - 1 hr = Faster speed time
\n" ); document.write( "\"200%2Fs\" - 1 = \"200%2F%28%28s%2B10%29%29\"
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\n" ); document.write( "Multiply equation by s(s+10)
\n" ); document.write( "s(s+10)*\"200%2Fs\" - s(s+10)(1) = s(s+10)*\"200%2F%28%28s%2B10%29%29\":
\n" ); document.write( "Cancel the denominators:
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\n" ); document.write( "200(s+10) - s(s+10) = 200s
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\n" ); document.write( "200s + 2000 - s^2 - 10s = 200s
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\n" ); document.write( "0 = s^2 + 10s + 200s - 200s - 2000
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\n" ); document.write( "A quadratic equation
\n" ); document.write( "s^2 + 10s - 2000 = 0
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\n" ); document.write( "Factors to:
\n" ); document.write( "(s+50)(s-40) = 0
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\n" ); document.write( "Positive solution
\n" ); document.write( "s = 40 mph
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\n" ); document.write( "Check solution by finding the times:
\n" ); document.write( "200/40 = 5 hrs
\n" ); document.write( "200/50 = 4 hrs\r
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