document.write( "Question 144840: \n" ); document.write( "
Algebra.Com's Answer #105541 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
There are 2 main things to know
\n" ); document.write( "1) You have to get \"k\" all by itself on one side of the equation
\n" ); document.write( "2) Anything you do to one side, you MUST do to the other side
\n" ); document.write( "So, first
\n" ); document.write( "Subtract \"3u\" from both sides
\n" ); document.write( "This is the same thing as adding these 2 equations together
\n" ); document.write( "\"-3u+=+-3u\"
\n" ); document.write( "\"t+=+3k+%2B+3u\"
\n" ); document.write( "Notice that the \"-3u\" and the \"3u\" on the right side cancel
\n" ); document.write( "So, now you have
\n" ); document.write( "\"t+-+3u+=+3k\"
\n" ); document.write( "Now divide both sides by \"3\"
\n" ); document.write( "\"%28t+-+3u%29+%2F+3+=+%283k%29+%2F+3\"
\n" ); document.write( "On the right side, the \"3\" in the denominator cancels the \"3\"
\n" ); document.write( "in the numerator
\n" ); document.write( "Now you have
\n" ); document.write( "\"%28t+-+3u%29+%2F+3+=+k\"
\n" ); document.write( "Now just rewrite the equation in the opposite direction
\n" ); document.write( "\"k+=+%28t+-+3u%29+%2F+3\"
\n" ); document.write( "And that's the answer
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