document.write( "Question 21909: ok! i have no earthly idea what anyone is talking about, i have final exams next week, i have a 46 in algebra right now, were in graphing and slopeing and stuff and i neeed some help. can anyone explain it simplier? \n" ); document.write( "
Algebra.Com's Answer #10551 by queenofit(120)![]() ![]() ![]() You can put this solution on YOUR website! I don't really understand what section you are talking about. \n" ); document.write( "But I will give you some tips, you can email me with examples of what you are having trouble with and I will try to help. athompson022@ntcc.edu. \n" ); document.write( "First, for slope you take the two sets of points you are given and put them like this and solve for slope \n" ); document.write( "slope = y2 - y1 your points will be shown as (x-y) (x2-y2) i only use 2 \n" ); document.write( " ------- to indicate which point you put in the first set of point \n" ); document.write( " X2 - X1 are x and y, the second set is x2 and y2, but do not use \n" ); document.write( " the 1 or 2s in your problem. for example points (1,1) \n" ); document.write( " and (2,4) you would set this up to find slope as follows \n" ); document.write( "m= 4-1 \n" ); document.write( " ---- = 3/1=3 so m=3 3 is your slope \n" ); document.write( " 2-1 \n" ); document.write( "------------------------------------------------------------------------------- \n" ); document.write( "To find the y intercept for an equation set x in your equation = 0 then solve for y. your answer would be something like (0,y). to find the x intercept set y=0 in your equation and slolve for x your answer would be (x,0). get it? \n" ); document.write( "------------------------------------------------------------------------------- \n" ); document.write( "an example of a question that was on my test for some of the things you may need are given below. I don't really know what you need, so maybe these will help.\r \n" ); document.write( "\n" ); document.write( "1. given -3x + 3y = 12, find the slope and y intercept. \n" ); document.write( "-3x+3y=12 you want this in the form y=mx+b with m being your slope \n" ); document.write( "3y=3x+12 \n" ); document.write( "y=3x/3 + 12/3 to get rid of the 3 in front of the y \n" ); document.write( "y=x+4 \n" ); document.write( "your slope would be 1 since there is only 1x. \n" ); document.write( " to get the yintercept, set x equal to zero and solve for y. \n" ); document.write( " the answer would be (0,y) this is the first point to plot on \n" ); document.write( " graph. since 3 is your slope you use 3/1. you have plotted \n" ); document.write( " your first point you move up 3 and over 1 to get the next point \n" ); document.write( " on the graph. then repeat the up 3 and over 1 for all the \n" ); document.write( " points you need. \n" ); document.write( "0 + 3y=12 \n" ); document.write( "3y=12 \n" ); document.write( "y=4 your first point would be (0,4), your y intercept \n" ); document.write( "------------------------------------------------------------------------------- \n" ); document.write( "2. you are asked to find the equation of the line passing through (6,-3) and parallel to 2y-6x=12 \n" ); document.write( "Remember if they are parallel they have the same slope. First put the equation into y=mx+b form \n" ); document.write( "2y=6x+12 you must get rid of the 2 in front of the y by dividing both sides \n" ); document.write( " by 2 \n" ); document.write( "y=3x+4 this is in y=mx+b form the slope is the m value.(#in front of x) \n" ); document.write( " you now have points and a slope and can use point-slope formula \n" ); document.write( " y-y2=m(x-x1) \n" ); document.write( "get the y1 and x1 values from your given points (6,-3)\r \n" ); document.write( "\n" ); document.write( "y+(-3)=3(x-6) this is in point slope formula \n" ); document.write( "y+3=3x-18 \n" ); document.write( "y=3x-3-18 \n" ); document.write( "y=3x-21 this is the equation of a line (y=mx+b) notice that the slopes are the same because they are parallel lines. \n" ); document.write( "------------------------------------------------------------------------------- \n" ); document.write( "For a perpendicular line, the slope is always the negative reciprocal of the slope of the first line. \n" ); document.write( "for example \n" ); document.write( "3. find the equation of the line passing through(5,3) and perpendicular to x=5y-7. \n" ); document.write( " first you must set the equation in y=mx+b form \n" ); document.write( "-5y=-x-7 I find it easier to change all the signs \n" ); document.write( "5y=x+7 you actually divide each side by -1 \n" ); document.write( "y=1/5x+7 this is in y=mx+b \n" ); document.write( " because the line is perpendicular, you use the negative reciprocal of 1/5 as your slope. that is -5 \n" ); document.write( "put it in the slope intercept form because you have a slope now and a set of points. \n" ); document.write( "y-3=-5(x-5) \n" ); document.write( "y-3=-5x+25 \n" ); document.write( "y=-5x+25+5 \n" ); document.write( "y=-5x+30 this is your equation for a perpendicular line in y=mx+b\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |