document.write( "Question 144737: what is the approximate srface area of a regular tetrahedron with edge length 12 cm? \n" ); document.write( "

Algebra.Com's Answer #105477 by Alan3354(69443) $\"\"$ $\"About$

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A regular tetrahedron is composed of 4 triangular faces, here all sides are 12\"
\n" ); document.write( "The area of a triangle is 1/2 of base times height, bh/2.
\n" ); document.write( "The height is $\"sqrt%2812%5E2-6%5E2%29\"$
\n" ); document.write( "h = $\"sqrt%28108%29\"$
\n" ); document.write( "The area of 1 triangle is $\"12sqrt%28108%29%2F2\"$
\n" ); document.write( "The total is 4 times this, or $\"24sqrt%28108%29\"$
\n" ); document.write( "Area = 249.415 square cm \n" ); document.write( "

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