document.write( "Question 144713: The difference between two positive numbers is 4. If twice the square of the larger number is added to three time the smaller, the sum is 53. \n" ); document.write( "
Algebra.Com's Answer #105449 by solver91311(24713)\"\" \"About 
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Larger positive number: \"x\"
\n" ); document.write( "Smaller positive number: \"y\"
\n" ); document.write( "Difference \"x-y=4\"
\n" ); document.write( "Twice the square of the larger:\"2x%5E2\"
\n" ); document.write( "Three times the smaller: \"3y\"
\n" ); document.write( "The sum is 53: \"2x%5E2%2B3y=53\"\r
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\n" ); document.write( "\n" ); document.write( "Re-write the difference equation: \"y=x-4\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute in the other equation: \"2x%5E2%2B3%28x-4%29=53\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3x-12-53=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3x-65=0\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic (it factors) for x. Discard the negative root since the question asked for a pair of positive numbers. Then subtract 4 to get y.
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