document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144660>Question 144660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a diagonal that is 3.6 feet longer than the length and 7.1 feet longer than the width. What are the dimensions of the rectangle? I would appreaciate it if someone could help me solve this problem. This is what I've done so far but I know its not correct. Thank you for your time. <BR>\n" );
document.write( "X^2 + (X+7.1)^2 = (X+3.6)^2 <BR>\n" );
document.write( "X^2 + X^2 + 14.2 + 50.41 = X^2 + 2X + 3.6 <BR>\n" );
document.write( "X^2+16.2X + 52.6=0<BR>\n" );
document.write( "(X=13.15)(X=4.05)        </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105435 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It looks like you intended for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > to represent the length of the diagonal.  If that is the case, and the diagonal is 3.6 feet longer than the length of the rectangle, then the length of the rectangle has to be 3.6 feet SHORTER than the diagonal.  Hence, the length of the rectangle would be represented by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+-+3.6 ALIGN=MIDDLE  ALT=\"x+-+3.6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Similarly, the width of the rectangle would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+-+7.1 ALIGN=MIDDLE  ALT=\"x+-+7.1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Since the diagonal is the hypotenuse of a right triangle, and the width and length of the rectangle are the legs of that triangle:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28x-3.6%29%5E2%2B%28x-7.1%29%5E2 ALIGN=MIDDLE  ALT=\"x%5E2=%28x-3.6%29%5E2%2B%28x-7.1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now expand that and solve the quadratic to get your dimensions.\r<BR>\n" );
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document.write( "By the way, since your given dimensions are expressed to the nearest 1/10 of a foot, your answer should not be expressed to any greater precision. </SPAN>\n" );
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