document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144667>Question 144667</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132319284/algebrahomeworkh>Prealgebra & Introductory Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the legs of a right triangle is 17 in. The longer leg is 2 more than twice the shorter. Th hypotenuse is 13 in. Find the length of each leg. Isn't the formula for a right triangle a^2 +b^2=c^2? From what I understand this is the way I would write to solve, but it doesn't make sense to me.\r<BR>\n" );
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document.write( "17=a^2+b^2+2<BR>\n" );
document.write( "a^2+b^2= 13^2\r<BR>\n" );
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document.write( "Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105428 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"shorter leg\"\r<BR>\n" );
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document.write( "\"The longer leg is 2 more than twice the shorter\" __ 2x+2\r<BR>\n" );
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document.write( "\"The sum of the legs of a right triangle is 17 in.\" __ x+2x+2=17\r<BR>\n" );
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document.write( "3x+2=17 __ 3x=15 __ x=5\r<BR>\n" );
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document.write( "substituting __ 2(5)+2=12\r<BR>\n" );
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document.write( "5,12,13 is a Pythagorean triple (like 3,4,5) __ 5^2+12^2=13^2 __ 25+144=169 </SPAN>\n" );
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