document.write( "Question 144667This question is from textbook Prealgebra & Introductory Algebra
\n" ); document.write( ": The sum of the legs of a right triangle is 17 in. The longer leg is 2 more than twice the shorter. Th hypotenuse is 13 in. Find the length of each leg. Isn't the formula for a right triangle a^2 +b^2=c^2? From what I understand this is the way I would write to solve, but it doesn't make sense to me.\r
\n" ); document.write( "\n" ); document.write( "17=a^2+b^2+2
\n" ); document.write( "a^2+b^2= 13^2\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help.
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Algebra.Com's Answer #105427 by solver91311(24713)\"\" \"About 
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Length of one leg: \"a\"\r
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\n" ); document.write( "\n" ); document.write( "Length of the other leg: \"b\"\r
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\n" ); document.write( "\n" ); document.write( "Assume \"b\" is the long leg, so \"b+=+2a+%2B+2\" (2 more than twice the shorter)\r
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\n" ); document.write( "\n" ); document.write( "Sum of the lengths of the legs: \"a+%2B+b+=+17\", but since \"b=2a%2B2\", \"a%2B2a%2B2=17\" by substitution.\r
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\n" ); document.write( "\n" ); document.write( "Collect like terms and solve for \"a\", \"3a%2B2=17\" => \"3a=15\" => \"a=5\"\r
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\n" ); document.write( "\n" ); document.write( "So: \"5+%2B+b+=+17\" => \"b=12\"\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"5%5E2%2B12%5E2=25%2B144=169=13%5E2\" Checks.\r
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\n" ); document.write( "\n" ); document.write( "Note that if we had assumed in the beginning that \"a\" was the longer leg, the result would have been that \"a=12\" and \"b=5\" -- same answer for all practical purposes.
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