document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144664>Question 144664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of an equilateral triangle in which the height is 3 square root of 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105411 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What you have is a right triangle with the height(3sqrt3) the other side (x) & the hypotenuse (2x)<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "x^2+(3sqrt3)^2=(2x)^2<BR>\n" );
document.write( "x^2+9*3=4x^2<BR>\n" );
document.write( "x^2+27-4x^2=0<BR>\n" );
document.write( "-3x^2=-27<BR>\n" );
document.write( "x^2=-27/-3<BR>\n" );
document.write( "x^2=9<BR>\n" );
document.write( "x=sqrt9<BR>\n" );
document.write( "x=3 for the short side.<BR>\n" );
document.write( "2*3=6 for the hypotenuse.<BR>\n" );
document.write( "area=3*3sqrt3<BR>\n" );
document.write( "area=9*1,732<BR>\n" );
document.write( "area=15.59 answer. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );