document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144643>Question 144643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, if anyone can tell me if I am in the right direction with this problem please.  <BR>\n" );
document.write( "Two boats leave a marina at the same time. Boat A travels at 20km/hr in a direction of 65 degrees. Boat B travels at 12.5km/hr in a direction of 145 degrees.  How far apart are the boats after 2 hours.  (2) In what direction would the skipper of Boat A have to look to see Boat B.  I have this.<BR>\n" );
document.write( "Boat A 20km x 2 hrs = 40 km<BR>\n" );
document.write( "Boat B 12.5 km x 2 hrs = 25 km.<BR>\n" );
document.write( "They are offset by an angle of 145-60 = 86 degrees. Using the Law of Cosines I get<BR>\n" );
document.write( "x^2 = 40^2 + 25^2 - 2(40)(25)cos(85 degrees) = 2050.688. so x^2 = 45.28.  The boats are 45.28 km apart after 2 hours.  However this just doesnt seem right to me.<BR>\n" );
document.write( "I have no idea how to answer part b.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105393 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You did it right, but the angle between the paths is 80 degs, not 86 or 85. That makes the distance 43.3325 km.<BR>\n" );
document.write( "Then, use the law of sines to determine the angle from boat A to B, which is 34.623 degs.  Looking from boat A back to the marina would be the recip or 65 degs, or 245 degs.  Subtract the 34.623 from that, giving 211.377 degs. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );